When you are working with root locus, you are making a figure about your characteristic equation behavior. So, the root locus of a negative-feedback loop is going to be the same at any point of the loop. Notice: the name 'characteristic equation' is just because of that. In your case, we have: characteristic equation = \$1 + \frac{1}{(s+3)(s+4)} \frac{K}{s(s+1)}\$ if K was in the open loop this will be the same.
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